Alison tried to find all the points on the curve given by x2+4y2=7+3xy where the line tangent to the curve is horizontal. This is her solution:Step 1: Finding an expression for dxdy.dxdy=8y−3x3y−2xStep 2: Forming a system of equations.⎩⎨⎧x2+4y2=7+3xy3y−2x=08y−3x=0Step 3: Solving the system.(3,2) and (−3,−2)Is Alison's solution correct? If not, at which step did she make a mistake?Choose 1 answer:(A) The solution is correct.(B) Step 1 is incorrect.(C) Step 2 is incorrect.(D) Step 3 is incorrect.
Q. Alison tried to find all the points on the curve given by x2+4y2=7+3xy where the line tangent to the curve is horizontal. This is her solution:Step 1: Finding an expression for dxdy.dxdy=8y−3x3y−2xStep 2: Forming a system of equations.⎩⎨⎧x2+4y2=7+3xy3y−2x=08y−3x=0Step 3: Solving the system.(3,2) and (−3,−2)Is Alison's solution correct? If not, at which step did she make a mistake?Choose 1 answer:(A) The solution is correct.(B) Step 1 is incorrect.(C) Step 2 is incorrect.(D) Step 3 is incorrect.
Differentiate implicitly: Find an expression for dxdy. To find where the tangent line to the curve is horizontal, we need to find where the derivative of y with respect to x, dxdy, is equal to 0. We start by differentiating the given equation implicitly with respect to x. Differentiating both sides of the equation x2+4y2=7+3xy with respect to x gives us: 2x+8yy′=3y+3xy′. Rearranging to solve for y′, we get: y0y1y2
Form system of equations: Form a system of equations.For the tangent to be horizontal, (dxdy) must be equal to 0. This gives us the system of equations:1. x2+4y2=7+3xy (original curve equation)2. 3y−2x=0 (horizontal tangent condition)3. 8y−3x=0 (denominator cannot be zero)
Solve the system: Solve the system.We need to solve the system of equations from Step 2. Let's start with the second equation:3y−2x=03y=2xy=32xNow we substitute y=32x into the first equation:x2+4(32x)2=7+3x(32x)x2+916x2=7+2x2Combining like terms, we get:925x2=7x2=2563x=±2563x=±537Now we find the corresponding y values using y=32x:3y=2x13y=2x2The points where the tangent is horizontal are therefore 3y=2x3 and 3y=2x4.Checking the third condition, we have:3y=2x53y=2x63y=2x73y=2x8, which is true.