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Alain throws a stone off a bridge into a river below. The stone's height (in meters above the water), x seconds after Alain threw it, is modeled by: h(x)=-5x^(2)+10 x+15 What is the height of the stone at the time it is thrown?

Alain throws a stone off a bridge into a river below.\newlineThe stone's height (in meters above the water), x x seconds after Alain threw it, is modeled by:\newlineh(x)=−5x2+10x+15 h(x)=-5 x^{2}+10 x+15 \newlineWhat is the height of the stone at the time it is thrown?

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Q. Alain throws a stone off a bridge into a river below.\newlineThe stone's height (in meters above the water), x x seconds after Alain threw it, is modeled by:\newlineh(x)=−5x2+10x+15 h(x)=-5 x^{2}+10 x+15 \newlineWhat is the height of the stone at the time it is thrown?
  1. Find Initial Height: We need to find the height of the stone at the time it is thrown, which corresponds to the height at x=0x = 0 seconds.\newlineThe height function is given by h(x)=−5x2+10x+15h(x) = -5x^2 + 10x + 15.\newlineTo find the height at the time it is thrown, we substitute x=0x = 0 into the height function.\newlineh(0)=−5(0)2+10(0)+15h(0) = -5(0)^2 + 10(0) + 15
  2. Substitute x=0x = 0: Now we perform the calculation with x=0x = 0.
    h(0)=−5(0)+10(0)+15h(0) = -5(0) + 10(0) + 15
    h(0)=0+0+15h(0) = 0 + 0 + 15
    h(0)=15h(0) = 15
    This means the height of the stone at the time it is thrown is 1515 meters.

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