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Ai Mi deposits 
$4,200 every year into an account earning an annual interest rate of 
8.1% compounded annually. How much would she have in the account after 3 years, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Ai Mi deposits $4,200 \$ 4,200 every year into an account earning an annual interest rate of 8.1% 8.1 \% compounded annually. How much would she have in the account after 33 years, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Ai Mi deposits $4,200 \$ 4,200 every year into an account earning an annual interest rate of 8.1% 8.1 \% compounded annually. How much would she have in the account after 33 years, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify variables: Identify the variables from the problem to use in the formula.\newlineWe have:\newlined=$4,200d = \$4,200 (the amount invested at the end of each period)\newlinei=8.1%i = 8.1\% or 0.0810.081 (the interest rate per period)\newlinen=3n = 3 (the number of periods)
  2. Convert interest rate: Convert the interest rate from a percentage to a decimal. i=8.1%=0.081i = 8.1\% = 0.081
  3. Plug values into formula: Plug the values into the compound interest formula to calculate the future value of the account.\newlineA=d×((1+i)n1)/iA = d \times \left(\left(1 + i\right)^n - 1\right) / i\newlineA=4200×((1+0.081)31)/0.081A = 4200 \times \left(\left(1 + 0.081\right)^3 - 1\right) / 0.081
  4. Calculate inside parentheses: Calculate the value inside the parentheses.\newline(1+i)n=(1+0.081)3(1 + i)^n = (1 + 0.081)^3\newline=1.0813= 1.081^3\newline=1.259712161= 1.259712161
  5. Subtract one: Continue the calculation by subtracting 11 from the result of Step 44.\newline1.2597121611=0.2597121611.259712161 - 1 = 0.259712161
  6. Divide by interest rate: Divide the result of Step 55 by the interest rate ii. \newline0.2597121610.081=3.208802975\frac{0.259712161}{0.081} = 3.208802975
  7. Multiply by amount: Multiply the result of Step 66 by the amount invested at the end of each period dd.A=4200×3.208802975A = 4200 \times 3.208802975A=13476.9737A = 13476.9737
  8. Round to nearest dollar: Round the result to the nearest dollar.\newlineA$13,477A \approx \$13,477

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