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A triangle has vertices on a coordinate grid at U(-6,-4),V(1,-4), and W(-6,7). What is the length, in units, of bar(UV) ? Answer: units

A triangle has vertices on a coordinate grid at U(−6,−4),V(1,−4) U(-6,-4), V(1,-4) , and W(−6,7) W(-6,7) . What is the length, in units, of UV‾ \overline{U V} ?\newlineAnswer: □\square units

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Q. A triangle has vertices on a coordinate grid at U(−6,−4),V(1,−4) U(-6,-4), V(1,-4) , and W(−6,7) W(-6,7) . What is the length, in units, of UV‾ \overline{U V} ?\newlineAnswer: □\square units
  1. Identify Points U and V: Identify the coordinates of points U and V.\newlinePoint U has coordinates (−6,−4)(-6, -4) and point V has coordinates (1,−4)(1, -4).
  2. Calculate Length of bar(UV): Use the distance formula to calculate the length of bar(UV). The distance formula is d=[(x2−x1)2+(y2−y1)2]d = \sqrt{[(x_2 - x_1)^2 + (y_2 - y_1)^2]}, where (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are the coordinates of two points. For bar(UV), we have (x1,y1)=(−6,−4)(x_1, y_1) = (-6, -4) and (x2,y2)=(1,−4)(x_2, y_2) = (1, -4).
  3. Plug Coordinates into Formula: Plug the coordinates into the distance formula.\newlined=[(1−(−6))2+(−4−(−4))2]d = \sqrt{[(1 - (-6))^2 + (-4 - (-4))^2]}\newlined=[(1+6)2+(0)2]d = \sqrt{[(1 + 6)^2 + (0)^2]}\newlined=[72+02]d = \sqrt{[7^2 + 0^2]}\newlined=[49+0]d = \sqrt{[49 + 0]}\newlined=[49]d = \sqrt{[49]}\newlined=7d = 7

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