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A triangle has vertices on a coordinate grid at
T(-10,1),U(9,1), and
V(9,-4). What is the length, in units, of
bar(TU) ?
Answer: units

A triangle has vertices on a coordinate grid at $T(-10,1), U(9,1)$ , and $V(9,-4)$ . What is the length, in units, of $\overline{T U}$ ? $\newline$ Answer: $\square$ units

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Calculate quartiles and interquartile range

Full solution

Q. A triangle has vertices on a coordinate grid at

T(-10,1), U(9,1)

, and

V(9,-4)

. What is the length, in units, of

\overline{T U}

?

\newline

Answer:

\square

units

Identify Coordinates: Identify the coordinates of points $T$ and $U$ . Point $T$ has coordinates $(-10, 1)$ and point $U$ has coordinates $(9, 1)$ .
Recognize Same Y-Coordinates: Recognize that the $y$ -coordinates of points $T$ and $U$ are the same. Since the $y$ -coordinates are the same, $\overline{TU}$ is a horizontal line segment.
Calculate Length: Calculate the length of bar( $TU$ ) using the difference in $x$ -coordinates. $\newline$ Length of bar( $TU$ ) = $x$ -coordinate of $U$ - $x$ -coordinate of $T$ $\newline$ Length of bar( $TU$ ) = $9 - (-10)$ $\newline$ Length of bar( $TU$ ) = $x$ $0$ $\newline$ Length of bar( $TU$ ) = $x$ $2$ units

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