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Let’s check out your problem:
A triangle has vertices on a coordinate grid at
E
(
−
9
,
−
10
)
,
F
(
−
9
,
9
)
E(-9,-10), F(-9,9)
E
(
−
9
,
−
10
)
,
F
(
−
9
,
9
)
, and
G
(
8
,
9
)
G(8,9)
G
(
8
,
9
)
. What is the length, in units, of
E
F
‾
\overline{E F}
EF
?
\newline
Answer:
□
\square
□
units
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Math Problems
Algebra 2
Write equations of hyperbolas in standard form using properties
Full solution
Q.
A triangle has vertices on a coordinate grid at
E
(
−
9
,
−
10
)
,
F
(
−
9
,
9
)
E(-9,-10), F(-9,9)
E
(
−
9
,
−
10
)
,
F
(
−
9
,
9
)
, and
G
(
8
,
9
)
G(8,9)
G
(
8
,
9
)
. What is the length, in units, of
E
F
‾
\overline{E F}
EF
?
\newline
Answer:
□
\square
□
units
Identify Coordinates:
Identify the coordinates of points
E
E
E
and
F
F
F
to calculate the distance between them.
\newline
E
(
−
9
,
−
10
)
E(-9,-10)
E
(
−
9
,
−
10
)
and
F
(
−
9
,
9
)
F(-9,9)
F
(
−
9
,
9
)
.
Recognize Bar EF:
Recognize that the
x
x
x
-coordinates of
E
E
E
and
F
F
F
are the same, which means that bar(
E
F
EF
EF
) is vertical.
Use Distance Formula:
Use the
distance formula
for points with the same
x
x
x
-coordinate: Distance =
∣
y
2
−
y
1
∣
|y_2 - y_1|
∣
y
2
−
y
1
∣
.
Substitute Y-Coordinates:
Substitute the
y
y
y
-coordinates of points
E
E
E
and
F
F
F
into the distance formula:
Distance
=
∣
9
−
(
−
10
)
∣
\text{Distance} = |9 - (-10)|
Distance
=
∣9
−
(
−
10
)
∣
.
Calculate Distance:
Calculate the distance:
Distance
=
∣
9
+
10
∣
=
∣
19
∣
\text{Distance} = |9 + 10| = |19|
Distance
=
∣9
+
10∣
=
∣19∣
.
Simplify Absolute Value:
Simplify the absolute value:
Distance
=
19
units
.
\text{Distance} = 19 \text{ units}.
Distance
=
19
units
.
More problems from Write equations of hyperbolas in standard form using properties
Question
Write the equation in standard form for the hyperbola
x
2
−
y
2
=
64
x^2 - y^2 = 64
x
2
−
y
2
=
64
.
\newline
______
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Posted 9 months ago
Question
What is the center of the hyperbola
4
x
2
−
y
2
−
100
=
0
4x^2 - y^2 - 100 = 0
4
x
2
−
y
2
−
100
=
0
?
\newline
(
_
,
_
)
(\_,\_)
(
_
,
_
)
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Posted 9 months ago
Question
What is the center of the hyperbola
(
x
2
144
)
−
(
y
2
81
)
=
1
(\frac{x^2}{144}) - (\frac{y^2}{81}) = 1
(
144
x
2
)
−
(
81
y
2
)
=
1
?
\newline
(_____,_____)
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Posted 9 months ago
Question
What is the length of the transverse axis of the hyperbola
(
x
2
64
)
−
(
y
2
36
)
=
1
(\frac{x^2}{64}) - (\frac{y^2}{36}) = 1
(
64
x
2
)
−
(
36
y
2
)
=
1
?
\newline
______
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Posted 9 months ago
Question
Write the equation in standard form for the hyperbola
y
2
−
x
2
=
81
y^2 - x^2 = 81
y
2
−
x
2
=
81
.
\newline
______
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Posted 9 months ago
Question
Write the equation in standard form for the hyperbola
x
2
−
4
y
2
=
100
x^2 - 4y^2 = 100
x
2
−
4
y
2
=
100
.
\newline
______
Get tutor help
Posted 9 months ago
Question
Write the equation in standard form for the hyperbola
9
y
2
−
x
2
=
36
9y^2 - x^2 = 36
9
y
2
−
x
2
=
36
.
\newline
______
Get tutor help
Posted 9 months ago
Question
Write the equation in standard form for the hyperbola
4
x
2
−
y
2
=
16
4x^2 - y^2 = 16
4
x
2
−
y
2
=
16
.
\newline
______
Get tutor help
Posted 9 months ago
Question
Write the equation in standard form for the hyperbola
y
2
−
9
x
2
=
144
y^2 - 9x^2 = 144
y
2
−
9
x
2
=
144
.
\newline
______
Get tutor help
Posted 9 months ago
Question
The graph of
y
=
f
(
x
+
3
)
y=f(x+3)
y
=
f
(
x
+
3
)
is shown. For which value of
x
x
x
, rounded to the nearest whole number, must
f
(
x
)
=
0
f(x)=0
f
(
x
)
=
0
?
Get tutor help
Posted 1 month ago
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