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A tennis ball is dropped from a certain height. Its height in feet is given by h(t)=-16t^(2)+20 where t represents the time in seconds after launch. What is the ball's initial height? Answer: feet

A tennis ball is dropped from a certain height. Its height in feet is given by h(t)=−16t2+20 h(t)=-16 t^{2}+20 where t t represents the time in seconds after launch. What is the ball's initial height?\newlineAnswer: feet

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Q. A tennis ball is dropped from a certain height. Its height in feet is given by h(t)=−16t2+20 h(t)=-16 t^{2}+20 where t t represents the time in seconds after launch. What is the ball's initial height?\newlineAnswer: feet
  1. Identify Equation: The equation given is h(t)=−16t2+20h(t)=-16t^{2}+20. To find the initial height, we need to determine the value of h(t)h(t) when t=0t = 0, since the initial height is the height of the ball at the time it is dropped, which is at time t=0t = 0.\newlineCalculation: h(0)=−16(0)2+20=20h(0) = -16(0)^{2} + 20 = 20

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