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A tennis ball is dropped from a certain height. Its height in feet is given by 
h=-16t^(2)+24 where 
t represents the time in seconds after launch. What is the ball's initial height?
Answer: feet

A tennis ball is dropped from a certain height. Its height in feet is given by h=16t2+24 h=-16 t^{2}+24 where t t represents the time in seconds after launch. What is the ball's initial height?\newlineAnswer: feet

Full solution

Q. A tennis ball is dropped from a certain height. Its height in feet is given by h=16t2+24 h=-16 t^{2}+24 where t t represents the time in seconds after launch. What is the ball's initial height?\newlineAnswer: feet
  1. Initial Height Determination: The equation given for the height of the tennis ball is h=16t2+24h=-16t^{2}+24. To find the initial height, we need to determine the value of hh when t=0t=0, since the initial height is the height of the ball at the time it is dropped.
  2. Substitute t=0t=0: Substitute t=0t=0 into the equation h=16t2+24h=-16t^{2}+24 to find the initial height.\newlineh=16(0)2+24h=-16(0)^{2}+24\newlineh=0+24h=0+24\newlineh=24h=24

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