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A survey was given to a random sample of voters in the United States to ask about their preference for a presidential candidate. The survey reported a confidence interval that between 
51.5% and 
56.5% of the population preferred Candidate A. What is the margin of error on the survey? Do not write 
+- on the margin of error.
Answer:______

A survey was given to a random sample of voters in the United States to ask about their preference for a presidential candidate. The survey reported a confidence interval that between 51.5% 51.5 \% and 56.5% 56.5 \% of the population preferred Candidate A. What is the margin of error on the survey? Do not write ± \pm on the margin of error.\newlineAnswer:________

Full solution

Q. A survey was given to a random sample of voters in the United States to ask about their preference for a presidential candidate. The survey reported a confidence interval that between 51.5% 51.5 \% and 56.5% 56.5 \% of the population preferred Candidate A. What is the margin of error on the survey? Do not write ± \pm on the margin of error.\newlineAnswer:________
  1. Find Margin of Error: To find the margin of error, subtract the lower bound of the confidence interval from the upper bound and then divide by 22.\newlineCalculation: (56.5%51.5%)/2(56.5\% - 51.5\%) / 2
  2. Subtract Upper and Lower Bounds: Now, do the subtraction: 56.5%51.5%=5%56.5\% - 51.5\% = 5\%
  3. Divide by 22: Next, divide the result by 22: 5%/2=2.5%5\% / 2 = 2.5\%

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