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A survey was given to a random sample of the residents of a town to determine whether they support a new plan to raise taxes in order to increase education spending. The percentage of people who said the supported the plan to raise taxes was 
63%. The margin of error for the survey was 
5%. Write a confidence interval for the percentage of the population that favors the plan.

A survey was given to a random sample of the residents of a town to determine whether they support a new plan to raise taxes in order to increase education spending. The percentage of people who said the supported the plan to raise taxes was 63% 63 \% . The margin of error for the survey was 5% 5 \% . Write a confidence interval for the percentage of the population that favors the plan.\newline(______,______)

Full solution

Q. A survey was given to a random sample of the residents of a town to determine whether they support a new plan to raise taxes in order to increase education spending. The percentage of people who said the supported the plan to raise taxes was 63% 63 \% . The margin of error for the survey was 5% 5 \% . Write a confidence interval for the percentage of the population that favors the plan.\newline(______,______)
  1. Calculate Lower Bound: Calculate the lower bound of the confidence interval by subtracting the margin of error from the percentage of people who support the plan. 63%5%=58%63\% - 5\% = 58\%
  2. Calculate Upper Bound: Calculate the upper bound of the confidence interval by adding the margin of error to the percentage of people who support the plan. \newline63%+5%=68%63\% + 5\% = 68\%
  3. Write Confidence Interval: Write the confidence interval using the lower and upper bounds.\newlineThe confidence interval is 58%58\% to 68%68\%.

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