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A submarine is diving toward the bottom of the ocean.
The depth 
D of the submarine, in feet below sea level, after 
t minutes have elapsed is given by the function 
D(t)=20+16 t.
The pressure, 
P, in pounds per square inch, exerted on the submarine at a depth of 
x feet is given by the function

P(x)=14.7+0.445 x". "
Which expression models the pressure exerted on the submarine as a function of the elapsed time, 
t, in minutes?
Choose 1 answer:
(A) 
235.2+27.12 t
(B) 
23.6+7.12 t
(C) 
255.2+7.12 t
(D) 
8.9+21.82 t

A submarine is diving toward the bottom of the ocean.\newlineThe depth D D of the submarine, in feet below sea level, after t t minutes have elapsed is given by the function D(t)=20+16t D(t)=20+16 t .\newlineThe pressure, P P , in pounds per square inch, exerted on the submarine at a depth of x x feet is given by the function\newlineP(x)=14.7+0.445x  P(x)=14.7+0.445 x \text { } \newlineWhich expression models the pressure exerted on the submarine as a function of the elapsed time, t t , in minutes?\newlineChoose 11 answer:\newline(A) 235.2+27.12t 235.2+27.12 t \newline(B) 23.6+7.12t 23.6+7.12 t \newline(C) 255.2+7.12t 255.2+7.12 t \newline(D) 8.9+21.82t 8.9+21.82 t

Full solution

Q. A submarine is diving toward the bottom of the ocean.\newlineThe depth D D of the submarine, in feet below sea level, after t t minutes have elapsed is given by the function D(t)=20+16t D(t)=20+16 t .\newlineThe pressure, P P , in pounds per square inch, exerted on the submarine at a depth of x x feet is given by the function\newlineP(x)=14.7+0.445x  P(x)=14.7+0.445 x \text { } \newlineWhich expression models the pressure exerted on the submarine as a function of the elapsed time, t t , in minutes?\newlineChoose 11 answer:\newline(A) 235.2+27.12t 235.2+27.12 t \newline(B) 23.6+7.12t 23.6+7.12 t \newline(C) 255.2+7.12t 255.2+7.12 t \newline(D) 8.9+21.82t 8.9+21.82 t
  1. Understand depth-time relationship: Understand the relationship between depth and time.\newlineThe depth of the submarine after tt minutes is given by the function D(t)=20+16tD(t) = 20 + 16t. This means that the submarine starts at a depth of 2020 feet below sea level and goes deeper by 1616 feet for every minute that passes.
  2. Understand pressure-depth relationship: Understand the relationship between pressure and depth. The pressure exerted on the submarine at a depth of xx feet is given by the function P(x)=14.7+0.445xP(x) = 14.7 + 0.445x. This means that the pressure at sea level (00 feet depth) is 14.714.7 pounds per square inch, and for every foot the submarine goes deeper, the pressure increases by 0.4450.445 pounds per square inch.
  3. Combine functions for pressure: Combine the two functions to express pressure as a function of time.\newlineTo find the pressure as a function of time, we need to substitute the expression for depth as a function of time into the pressure function. This means we will replace xx in P(x)P(x) with D(t)D(t) from the first function.\newlineP(t)=P(D(t))=14.7+0.445(D(t))P(t) = P(D(t)) = 14.7 + 0.445(D(t))
  4. Substitute depth into pressure function: Substitute D(t)D(t) into the pressure function.\newlineNow we substitute D(t)=20+16tD(t) = 20 + 16t into the pressure function.\newlineP(t)=14.7+0.445(20+16t)P(t) = 14.7 + 0.445(20 + 16t)
  5. Distribute and simplify: Distribute 0.4450.445 across the terms inside the parentheses.\newlineP(t)=14.7+0.445×20+0.445×16tP(t) = 14.7 + 0.445 \times 20 + 0.445 \times 16t\newlineP(t)=14.7+8.9+7.12tP(t) = 14.7 + 8.9 + 7.12t
  6. Combine terms for final expression: Combine like terms to simplify the expression.\newlineP(t)=14.7+8.9+7.12tP(t) = 14.7 + 8.9 + 7.12t\newlineP(t)=23.6+7.12tP(t) = 23.6 + 7.12t

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