A string is divided into 5 parts with lengths forming a geometric sequence. If the shortest string is 16 cm and the longest string is 81 cm, then the original length of the string is ___
Q. A string is divided into 5 parts with lengths forming a geometric sequence. If the shortest string is 16 cm and the longest string is 81 cm, then the original length of the string is ___
Given Information: We are given that the string is divided into 5 parts with lengths forming a geometric sequence. The shortest part is 16 cm and the longest part is 81 cm. In a geometric sequence, each term after the first is found by multiplying the previous term by a constant called the common ratio (r). We need to find the common ratio and then use it to find the sum of the sequence, which will give us the original length of the string.
Equation for Longest String: Let's denote the shortest string as a (the first term of the geometric sequence). The longest string will be a×r(n−1), where n is the number of terms, which is 5 in this case. We can set up the equation for the longest string as follows:a×r(5−1)=81cmSince we know the shortest string is 16cm, we can substitute a with 16cm:16×r4=81
Finding Common Ratio: To find the common ratio r, we need to solve the equation:16⋅r4=81Divide both sides by 16 to isolate r4:r4=1681r4=5.0625Now, take the fourth root of both sides to find r:r=(5.0625)41r≈1.5
Finding Sum of Geometric Sequence: Now that we have the common ratio, we can find the sum of the geometric sequence using the formula for the sum of the first n terms of a geometric sequence: Sn=a×(1−rn)/(1−r) where Sn is the sum of the first n terms, a is the first term, r is the common ratio, and n is the number of terms. We have a=16 cm, r≈1.5, and n=5.
Finding Sum of Geometric Sequence: Now that we have the common ratio, we can find the sum of the geometric sequence using the formula for the sum of the first n terms of a geometric sequence: Sn=a⋅1−r1−rn where Sn is the sum of the first n terms, a is the first term, r is the common ratio, and n is the number of terms. We have a=16 cm, r≈1.5, and n=5. Let's plug the values into the sum formula: S5=16⋅1−1.51−1.55S5=16⋅1−1.51−7.59375S5=16⋅−0.5−6.59375S5=16⋅13.1875 \[S_5 = \(211\)\) cm