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A sequence starts at 1010. The term-to-term rule is to subtract 33 then multiply by 22 each time.\newlinea) Work out the fourth term of the sequence.\newlineb) Is this sequence increasing, decreasing or neither?

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Q. A sequence starts at 1010. The term-to-term rule is to subtract 33 then multiply by 22 each time.\newlinea) Work out the fourth term of the sequence.\newlineb) Is this sequence increasing, decreasing or neither?
  1. Start at 1010: The sequence starts at 1010, and the term-to-term rule is to subtract 33 and then multiply by 22. To find the first term after the initial value, we apply the rule to the starting number.\newlineFirst term (starting value): 1010\newlineSecond term calculation: (103)×2(10 - 3) \times 2
  2. Calculate second term: Now we calculate the second term using the term-to-term rule.\newlineSecond term: (103)×2=7×2=14(10 - 3) \times 2 = 7 \times 2 = 14
  3. Find third term: Next, we apply the term-to-term rule to the second term to find the third term.\newlineThird term calculation: (143)×2(14 - 3) \times 2
  4. Calculate fourth term: We calculate the third term.\newlineThird term: (143)×2=11×2=22(14 - 3) \times 2 = 11 \times 2 = 22
  5. Determine sequence pattern: We apply the term-to-term rule to the third term to find the fourth term.\newlineFourth term calculation: (223)×2(22 - 3) \times 2
  6. Determine sequence pattern: We apply the term-to-term rule to the third term to find the fourth term.\newlineFourth term calculation: (223)×2(22 - 3) \times 2 We calculate the fourth term.\newlineFourth term: (223)×2=19×2=38(22 - 3) \times 2 = 19 \times 2 = 38
  7. Determine sequence pattern: We apply the term-to-term rule to the third term to find the fourth term.\newlineFourth term calculation: (223)×2(22 - 3) \times 2 We calculate the fourth term.\newlineFourth term: (223)×2=19×2=38(22 - 3) \times 2 = 19 \times 2 = 38 To determine if the sequence is increasing, decreasing, or neither, we observe the pattern of the terms. We started with 1010, then the sequence went to 1414, 2222, and 3838. Each term is larger than the previous term, which indicates the sequence is increasing.

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