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A sequence is defined by
f(0)=-21,f(n)=f(n-1)-5 for
n >= 1 Explain why

f(1)=-21-5

$1$ . A sequence is defined by $f(0)=-21, f(n)=f(n-1)-5$ for $n \geq 1$ Explain why $\newline$ $f(1)=-21-5$

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Simplify radical expressions with variables II

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111. A sequence is defined by f(0)=−21,f(n)=f(n−1)−5 f(0)=-21, f(n)=f(n-1)-5 f(0)=−21,f(n)=f(n−1)−5 for n≥1 n \geq 1 n≥1 Explain why\newlinef(1)=−21−5f(1)=-21-5f(1)=−21−5

$1$ . A sequence is defined by $f(0)=-21, f(n)=f(n-1)-5$ for $n \geq 1$ Explain why $\newline$ $f(1)=-21-5$