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A sequence is defined by
f(0)=-21,f(n)=f(n-1)-5 for
n >= 1
Explain why

f(1)=-21-5
Show Your Work

$1$ . A sequence is defined by $f(0)=-21, f(n)=f(n-1)-5$ for $n \geq 1$ $\newline$ Explain why $\newline$ $f(1)=-21-5$ $\newline$ Show Your Work

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Algebra 2

Simplify radical expressions with variables II

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More problems from Simplify radical expressions with variables II

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Find the real-number root.

\newline

\sqrt{16}

\newline

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Write your answer in simplified form.

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Question

Find the real-number root.

\newline

\sqrt{\frac{9}{16}}

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Simplify your answer and write it as a decimal or as a proper or improper fraction.

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Find the real-number root using a calculator. Round your answer to the nearest thousandth.

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Multiply. Write your answer in simplest form.

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\sqrt{273} \times \sqrt{42}

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Simplify.

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Simplify. Rationalize the denominator.

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Solve for

z

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Question

Simplify the radical expression.

\sqrt{14x^{14}}

Write your answer in the form

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, or

A\sqrt{B}

, where

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and

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. Use at most one radical in your answer, and at most one absolute value symbol in your expression for

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Question

Simplify the radical expression.

\newline

\sqrt{12x^{12}}

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\newline

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Question

What is the value of

\sin \left(\frac{5 \pi}{6}\right) ?

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(D)

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Posted 8 months ago

View all (62)

111. A sequence is defined by f(0)=−21,f(n)=f(n−1)−5 f(0)=-21, f(n)=f(n-1)-5 f(0)=−21,f(n)=f(n−1)−5 for n≥1 n \geq 1 n≥1\newlineExplain why\newlinef(1)=−21−5f(1)=-21-5f(1)=−21−5\newlineShow Your Work

$1$ . A sequence is defined by $f(0)=-21, f(n)=f(n-1)-5$ for $n \geq 1$ $\newline$ Explain why $\newline$ $f(1)=-21-5$ $\newline$ Show Your Work