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A parabola opening up or down has vertex (0,7)(0,-7) and passes through (10,18)(-10,18). Write its equation in vertex form.\newlineSimplify any fractions.

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Q. A parabola opening up or down has vertex (0,7)(0,-7) and passes through (10,18)(-10,18). Write its equation in vertex form.\newlineSimplify any fractions.
  1. Vertex form of parabola: What is the vertex form of the parabola?\newlineVertex form of parabola: y=a(xh)2+ky = a(x - h)^2 + k
  2. Equation with vertex: What is the equation of a parabola with a vertex at (0,7)(0, -7)?\newlineSubstitute 00 for hh and 7-7 for kk in vertex form.\newliney=a(x0)2+(7)y = a(x - 0)^2 + (-7)\newliney=ax27y = ax^2 - 7
  3. Substitute values: y=ax27y = ax^2 - 7\newlineReplace the variables with (10,18)(-10, 18) in the equation.\newlineSubstitute 10-10 for xx and 1818 for yy.\newline18=a(10)2718 = a(-10)^2 - 7\newline18=100a718 = 100a - 7
  4. Solve for aa: 18=100a718 = 100a - 7\newlineSolve for aa.\newline18+7=100a18 + 7 = 100a\newline25=100a25 = 100a\newline25100=a\frac{25}{100} = a\newline14=a\frac{1}{4} = a
  5. Equation with a=14a=\frac{1}{4}: y=ax27y = ax^2 - 7\newlineWhat is the equation of the parabola if a=14a = \frac{1}{4}?\newlineSubstitute 14\frac{1}{4} for aa.\newliney=(14)x27y = (\frac{1}{4})x^2 - 7\newlineVertex form of parabola: y=(14)x27y = (\frac{1}{4})x^2 - 7

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