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A parabola opening up or down has vertex (0,6)(0,6) and passes through (6,3)(-6,-3). Write its equation in vertex form.\newlineSimplify any fractions.

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Q. A parabola opening up or down has vertex (0,6)(0,6) and passes through (6,3)(-6,-3). Write its equation in vertex form.\newlineSimplify any fractions.
  1. Find 'a' Value: Now we need to find the value of ' extit{a}' using the point extit{(6-6,3-3)} that lies on the parabola.
  2. Solve for ' extit{a}': Next, we solve for ' extit{a}' by isolating it on one side of the equation.
  3. Substitute 'aa' Value: Finally, we substitute the value of 'aa' back into the vertex form equation to get the equation of the parabola.

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