Q. A parabola opening up or down has vertex (0,6) and passes through (4,2). Write its equation in vertex form.Simplify any fractions.
Find 'a' Value: Now we need to find the value of ' extit{a}'. We know that the parabola passes through the point (4,2). We can substitute x=4 and y=2 into the equation to find ' extit{a}'.
Isolate 'a': Next, we solve for 'a' by isolating it on one side of the equation.
Write Final Equation: Now that we have the value of a, we can write the final equation of the parabola in vertex form.
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