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A parabola opening up or down has vertex (0,1)(0,-1) and passes through (8,9)(-8,-9). Write its equation in vertex form.\newlineSimplify any fractions.

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Q. A parabola opening up or down has vertex (0,1)(0,-1) and passes through (8,9)(-8,-9). Write its equation in vertex form.\newlineSimplify any fractions.
  1. Vertex Form Explanation: What is the vertex form of the parabola?\newlineThe vertex form of a parabola is given by the equation y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Vertex at (0,1)(0, -1): What is the equation of a parabola with a vertex at (0,1)(0, -1)?\newlineSince the vertex is (0,1)(0, -1), we substitute h=0h = 0 and k=1k = -1 into the vertex form equation.\newliney=a(x0)21y = a(x - 0)^2 - 1\newliney=ax21y = ax^2 - 1
  3. Use Point (8,9)(-8, -9): Use the point (8,9)(-8, -9) to find the value of aa. The parabola passes through the point (8,9)(-8, -9), so we substitute x=8x = -8 and y=9y = -9 into the equation to solve for aa. 9=a(8)21-9 = a(-8)^2 - 1 9=64a1-9 = 64a - 1
  4. Solve for 'a': Solve for 'a'.\newlineAdd 11 to both sides of the equation to isolate the term with 'a'.\newline9+1=64a1+1-9 + 1 = 64a - 1 + 1\newline8=64a-8 = 64a\newlineNow, divide both sides by 6464 to solve for 'a'.\newline8/64=a-8 / 64 = a\newline1/8=a-1 / 8 = a
  5. Final Equation in Vertex Form: Write the equation of the parabola in vertex form using the value of aa.\newlineNow that we have found aa to be 18-\frac{1}{8}, we substitute it back into the equation y=ax21y = ax^2 - 1.\newliney=(18)x21y = \left(-\frac{1}{8}\right)x^2 - 1\newlineThis is the equation of the parabola in vertex form.

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