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A parabola opening up or down has vertex (0,0)(0,0) and passes through (10,5)(10,5). Write its equation in vertex form.\newlineSimplify any fractions.\newline______

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Q. A parabola opening up or down has vertex (0,0)(0,0) and passes through (10,5)(10,5). Write its equation in vertex form.\newlineSimplify any fractions.\newline______
  1. Vertex Form: What is the vertex form of the parabola?\newlineVertex form of a parabola: y=a(xh)2+ky = a(x - h)^2 + k
  2. Equation at (0,0)(0,0): What is the equation of a parabola with a vertex at (0,0)(0, 0)?\newlineSubstitute 00 for hh and 00 for kk in vertex form.\newliney=a(x0)2+0y = a(x - 0)^2 + 0\newliney=ax2y = ax^2
  3. Substitute (10,5)(10,5): y=ax2y = ax^2\newlineReplace the variables with (10,5)(10, 5) in the equation.\newlineSubstitute 1010 for xx and 55 for yy.\newline5=a(10)25 = a(10)^2\newline5=100a5 = 100a
  4. Solve for aa: 5=100a5 = 100a\newlineSolve for aa.\newline5100=a\frac{5}{100} = a\newline120=a\frac{1}{20} = a
  5. Equation with a=120a=\frac{1}{20}: y=ax2y = ax^2\newlineWhat is the equation of the parabola if a=120a = \frac{1}{20}?\newlineSubstitute 120\frac{1}{20} for aa.\newliney=(120)x2y = \left(\frac{1}{20}\right)x^2\newlineVertex form of parabola: y=(120)x2y = \left(\frac{1}{20}\right)x^2

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