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A parabola opening up or down has vertex (0,0)(0,0) and passes through (2,1)(2,-1). Write its equation in vertex form.\newlineSimplify any fractions.

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Q. A parabola opening up or down has vertex (0,0)(0,0) and passes through (2,1)(2,-1). Write its equation in vertex form.\newlineSimplify any fractions.
  1. Vertex Form: What is the vertex form of the parabola?\newlineVertex form of parabola: y=a(xh)2+ky = a(x - h)^2 + k
  2. Equation at (00, 00): What is the equation of a parabola with a vertex at (0,0)(0, 0)?\newlineSubstitute 00 for hh and 00 for kk in vertex form.\newliney=a(x0)2+0y = a(x - 0)^2 + 0\newliney=ax2y = ax^2
  3. Substitute Values: y=ax2y = ax^2\newlineReplace the variables with (2,1)(2, -1) in the equation.\newlineSubstitute 22 for xx and 1-1 for yy.\newline1=a(2)2-1 = a(2)^2\newline1=4a-1 = 4a
  4. Solve for aa: 1=4a-1 = 4a\newlineSolve for aa.\newline14=a-\frac{1}{4} = a
  5. Equation with a=14a = -\frac{1}{4}: y=ax2y = ax^2\newlineWhat is the equation of the parabola if a=14a = -\frac{1}{4}?\newlineSubstitute 14-\frac{1}{4} for aa.\newliney=(14)x2y = (-\frac{1}{4})x^2\newlineVertex form of parabola: y=14x2y = -\frac{1}{4}x^2

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