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A new shopping mall records 150 total shoppers on their first day of business. Each day after that, the number of shoppers is 
15% more than the number of shoppers the day before.
Which expression gives the total number of shoppers in the first 
n days of business?
Choose 1 answer:
(A) 
1.15((1-150^(n))/(1-150))
(B) 
0.85((1-150^(n))/(1-150))
(C) 
150((1-1.15^(n))/(1-1.15))
(D) 
150((1-0.85^(n))/(1-0.85))

A new shopping mall records 150150 total shoppers on their first day of business. Each day after that, the number of shoppers is 15%15\% more than the number of shoppers the day before.\newlineWhich expression gives the total number of shoppers in the first nn days of business?\newlineChoose 11 answer:\newline(A) 1.15(1150n1150)1.15\left(\frac{1-150^n}{1-150}\right)\newline(B) 0.85(1150n1150)0.85\left(\frac{1-150^n}{1-150}\right)\newline(C) 150(11.15n11.15)150\left(\frac{1-1.15^n}{1-1.15}\right)\newline(D) 150(10.85n10.85)150\left(\frac{1-0.85^n}{1-0.85}\right)

Full solution

Q. A new shopping mall records 150150 total shoppers on their first day of business. Each day after that, the number of shoppers is 15%15\% more than the number of shoppers the day before.\newlineWhich expression gives the total number of shoppers in the first nn days of business?\newlineChoose 11 answer:\newline(A) 1.15(1150n1150)1.15\left(\frac{1-150^n}{1-150}\right)\newline(B) 0.85(1150n1150)0.85\left(\frac{1-150^n}{1-150}\right)\newline(C) 150(11.15n11.15)150\left(\frac{1-1.15^n}{1-1.15}\right)\newline(D) 150(10.85n10.85)150\left(\frac{1-0.85^n}{1-0.85}\right)
  1. Understand the problem: Understand the problem.\newlineWe need to find an expression that represents the total number of shoppers over the first nn days, given that each day has 15%15\% more shoppers than the previous day.
  2. Recognize the pattern: Recognize the pattern.\newlineThe number of shoppers increases by a factor of 1.151.15 each day. This is a geometric sequence where the first term is 150150 and the common ratio is 1.151.15.
  3. Write the formula: Write the formula for the sum of a geometric series.\newlineThe sum SS of the first nn terms of a geometric series with first term aa and common ratio rr is given by S=a(1rn)1rS = \frac{a(1 - r^n)}{1 - r}, provided r1r \neq 1.
  4. Apply the formula: Apply the formula to the problem.\newlineIn this case, a=150a = 150 (the number of shoppers on the first day) and r=1.15r = 1.15 (the growth factor). Plugging these values into the formula gives us S=150(11.15n)(11.15)S = \frac{150(1 - 1.15^n)}{(1 - 1.15)}.
  5. Check the answer choices: Check the answer choices.\newlineWe need to find which option matches the expression we derived. Option (C) is 150(11.15n11.15)150\left(\frac{1-1.15^{n}}{1-1.15}\right), which is the correct expression for the sum of a geometric series with the given values.

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