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a(n)=-6-4(n-1)
Find the 
4^("th ") term in the sequence.

a(n)=64(n1) a(n)=-6-4(n-1) \newlineFind the 4th  4^{\text {th }} term in the sequence.

Full solution

Q. a(n)=64(n1) a(n)=-6-4(n-1) \newlineFind the 4th  4^{\text {th }} term in the sequence.
  1. Understand the formula: Understand the sequence formula.\newlineThe given sequence is defined by the formula a(n)=64(n1)a(n) = -6 - 4(n - 1). This is an arithmetic sequence where each term is generated by starting with 6-6 and subtracting 44 times the quantity (n1)(n - 1), where nn is the position of the term in the sequence.
  2. Substitute nn with 44: Substitute nn with 44 to find the 44th term.\newlineTo find the 44th term, a(4)a(4), we substitute nn with 44 in the formula: a(4)=64(41)a(4) = -6 - 4(4 - 1).
  3. Perform calculation inside parentheses: Perform the calculation inside the parentheses.\newlineCalculate the value inside the parentheses: 41=34 - 1 = 3.\newlineSo, a(4)=64(3)a(4) = -6 - 4(3).
  4. Multiply 44 by 33: Multiply 44 by 33.\newlineNow, multiply 44 by 33 to get 1212: 4×3=124 \times 3 = 12.\newlineSo, a(4)=612a(4) = -6 - 12.
  5. Subtract 1212 from 6-6: Subtract 1212 from 6-6. Finally, subtract 1212 from 6-6 to find the 44th term: a(4)=612=18a(4) = -6 - 12 = -18.

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