a(n)=-6+3(n-1) Find the 16^("th ") term in the sequence.

Identify sequence type and formula: Identify the type of sequence and the formula given. The formula a(n) = -6 + 3(n - 1) defines an arithmetic sequence because the (n - 1) term indicates a constant difference between terms.Determine common difference: Determine the common difference of the sequence. The common difference is the coefficient of n in the formula, which is 3.Calculate 16th term: Calculate the 16th term using the formula. Substitute n with 16 in the formula a(n) = -6 + 3(n - 1). a(16) = -6 + 3(16 - 1) a(16) = -6 + 3(15) a(16) = -6 + 45 a(16) = 39

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a(n)=-6+3(n-1)
Find the
16^("th ") term in the sequence.

$a(n)=-6+3(n-1)$ $\newline$ Find the $16^{\text {th }}$ term in the sequence.

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a(n)=-6+3(n-1)

\newline

Find the

16^{\text {th }}

term in the sequence.

Identify sequence type and formula: Identify the type of sequence and the formula given. $\newline$ The formula $a(n) = -6 + 3(n - 1)$ defines an arithmetic sequence because the $(n - 1)$ term indicates a constant difference between terms.
Determine common difference: Determine the common difference of the sequence. $\newline$ The common difference is the coefficient of $n$ in the formula, which is $3$ .
Calculate $16$ th term: Calculate the $16$ th term using the formula. $\newline$ Substitute $n$ with $16$ in the formula $a(n) = -6 + 3(n - 1)$ . $\newline$ $a(16) = -6 + 3(16 - 1)$ $\newline$ $a(16) = -6 + 3(15)$ $\newline$ $a(16) = -6 + 45$ $\newline$ $a(16) = 39$