a(n)=-(1)/(16)(2)^(n-1) What is the 4^("th ") term in the sequence?

Step 1: Understand sequence formula: Understand the sequence formula and identify the term to find. The sequence is defined by the formula a(n) = -(1/16)(2)^(n-1). We need to find the 4th term, which means we will substitute n with 4 in the formula.Step 2: Substitute n with 4: Substitute n with 4 in the sequence formula. a(4) = -(1/16)(2)^(4-1)Step 3: Calculate the exponent: Calculate the exponent part of the formula. 2^(4-1) = 2^3 = 8Step 4: Multiply by -(1/16): Multiply the result of the exponentiation by -(1/16). a(4) = -(1/16) * 8Step 5: Perform the multiplication: Perform the multiplication to find the 4th term. a(4) = -8/16 a(4) = -1/2

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a(n)=-(1)/(16)(2)^(n-1)
What is the
4^("th ") term in the sequence?

$a(n)=-\frac{1}{16}(2)^{n-1}$ $\newline$ What is the $4^{\text {th }}$ term in the sequence?

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a(n)=-\frac{1}{16}(2)^{n-1}

\newline

What is the

4^{\text {th }}

term in the sequence?

Step $1$ : Understand sequence formula: Understand the sequence formula and identify the term to find. $\newline$ The sequence is defined by the formula $a(n) = -\left(\frac{1}{16}\right)(2)^{n-1}$ . We need to find the $4^{\text{th}}$ term, which means we will substitute $n$ with $4$ in the formula.
Step $2$ : Substitute $n$ with $4$ : Substitute $n$ with $4$ in the sequence formula. $a(4) = -\left(\frac{1}{16}\right)(2)^{(4-1)}$
Step $3$ : Calculate the exponent: Calculate the exponent part of the formula. $2^{(4-1)} = 2^3 = 8$
Step $4$ : Multiply by $-(\frac{1}{16})$ : Multiply the result of the exponentiation by $-(\frac{1}{16})$ . $\newline$ $a(4) = -(\frac{1}{16}) \times 8$
Step $5$ : Perform the multiplication: Perform the multiplication to find the $4^{\text{th}}$ term. $a(4) = \frac{-8}{16}$ $a(4) = \frac{-1}{2}$