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A line with a slope of −9-9 passes through the points (−2,j)(-2,j) and (−4,8)(-4,8). What is the value of jj?\newlinej=___j = \_\_\_

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Q. A line with a slope of −9-9 passes through the points (−2,j)(-2,j) and (−4,8)(-4,8). What is the value of jj?\newlinej=___j = \_\_\_
  1. Identify slope formula: Step 11: Identify the formula for the slope between two points.\newlineThe slope formula is (y2−y1)/(x2−x1)(y_2 - y_1) / (x_2 - x_1). Here, we know the slope is −9-9, and the points are (−2,j)(-2, j) and (−4,8)(-4, 8).
  2. Substitute known values: Step 22: Substitute the known values into the slope formula.\newlineUsing the points (−2,j)(-2, j) as (x1,y1)(x_1, y_1) and (−4,8)(-4, 8) as (x2,y2)(x_2, y_2), the formula becomes:\newline(−9(-9) = (8−j)/(−4+2)(8 - j) / (-4 + 2)
  3. Simplify denominator and solve: Step 33: Simplify the denominator and solve for jj.−4+2=−2-4 + 2 = -2, so:−9=8−j−2-9 = \frac{8 - j}{-2}Multiply both sides by −2-2 to clear the denominator:18=8−j18 = 8 - j
  4. Solve for j: Step 44: Solve for j.\newline18−8=j18 - 8 = j\newlinej=10j = 10

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