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A line with a slope of −7-7 passes through the points (2,d)(2,d) and (1,10)(1,10). What is the value of dd?\newlined = ____

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Q. A line with a slope of −7-7 passes through the points (2,d)(2,d) and (1,10)(1,10). What is the value of dd?\newlined = ____
  1. Calculate Slope: Points: (2,d)(2, d) and (1,10)(1, 10)\newlineSlope: −7-7\newlineUse the slope formula to relate the points and the slope.\newlineSlope =y2−y1x2−x1= \frac{y_2 - y_1}{x_2 - x_1}\newline−7=10−d1−2-7 = \frac{10 - d}{1 - 2}
  2. Simplify Equation: −7=10−d1−2-7 = \frac{10 - d}{1 - 2}\newlineSimplify the denominator of the right side of the equation.\newline−7=10−d−1-7 = \frac{10 - d}{-1}
  3. Isolate Variable: −7=(10−d)−1-7 = \frac{(10 - d)}{-1}\newlineMultiply both sides by −1-1 to isolate the term with dd.\newline−7×−1=(10−d)−1×−1-7 \times -1 = \frac{(10 - d)}{-1} \times -1\newline7=10−d7 = 10 - d
  4. Solve for dd: 7=10−d7 = 10 - d\newlineSolve for dd by moving the terms around.\newline7−10=−d7 - 10 = -d\newline−3=−d-3 = -d\newlined=3d = 3

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