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A line with a slope of 77 passes through the points (0,5)(0,5) and (1,p)(-1,p). What is the value of pp?

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Q. A line with a slope of 77 passes through the points (0,5)(0,5) and (1,p)(-1,p). What is the value of pp?
  1. Calculate Slope: Points: (0,5)(0, 5) and (1,p)(-1, p)\newlineSlope: 77\newlineWe will use the slope formula to find the value of pp.\newlineSlope = y2y1x2x1\frac{y_2 - y_1}{x_2 - x_1}\newline7=p5107 = \frac{p - 5}{-1 - 0}
  2. Simplify Equation: 7=p5107 = \frac{p - 5}{-1 - 0}\newlineSimplify the denominator.\newline7=p517 = \frac{p - 5}{-1}
  3. Isolate Variable: 7=(p5)(1)7 = \frac{(p - 5)}{(-1)}\newlineMultiply both sides by 1-1 to isolate (p5)(p - 5).\newline7×(1)=(p5)(1)×(1)7 \times (-1) = \frac{(p - 5)}{(-1)} \times (-1)\newline7=p5-7 = p - 5
  4. Solve for pp: 7=p5-7 = p - 5\newlineAdd 55 to both sides to solve for pp.\newline7+5=p5+5-7 + 5 = p - 5 + 5\newline2=p-2 = p

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