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A line with a slope of 55 passes through the points (4,j)(4,j) and (2,−5)(2,-5). What is the value of jj?\newlinej=___j = \_\_\_

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Full solution

Q. A line with a slope of 55 passes through the points (4,j)(4,j) and (2,−5)(2,-5). What is the value of jj?\newlinej=___j = \_\_\_
  1. Use slope formula: Use the slope formula to find jj. The slope formula is (y2−y1)/(x2−x1)(y_2 - y_1) / (x_2 - x_1). Here, (x1,y1)=(4,j)(x_1, y_1) = (4, j) and (x2,y2)=(2,−5)(x_2, y_2) = (2, -5).
  2. Simplify and solve: Simplify and solve for jj. Since (2−4)=−2(2 - 4) = -2, the equation becomes:\newline5=(−5−j)/−25 = (-5 - j) / -2\newlineMultiply both sides by −2-2 to clear the fraction:\newline−10=−5−j-10 = -5 - j
  3. Solve for jj: Solve for jj: −10+5=−j\ -10 + 5 = -j −5=−j\ -5 = -j j=5\ j = 5

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