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A line with a slope of −4-4 passes through the points (0,s)(0,s) and (−1,−1)(-1,-1). What is the value of ss?

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Full solution

Q. A line with a slope of −4-4 passes through the points (0,s)(0,s) and (−1,−1)(-1,-1). What is the value of ss?
  1. Slope Formula: The slope of a line passing through two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the formula:\newlineslope = y2−y1x2−x1\frac{y_2 - y_1}{x_2 - x_1}\newlineWe know the slope is −4-4, and we have the points (0,s)(0, s) and (−1,−1)(-1, -1). Let's plug these values into the slope formula.
  2. Calculate Slope: Using the slope formula with our points:\newline−4=s−(−1)0−(−1)-4 = \frac{s - (-1)}{0 - (-1)}\newline−4=s+11-4 = \frac{s + 1}{1}\newlineNow we need to solve for ss.
  3. Isolate ss: Multiply both sides of the equation by 11 to isolate ss on one side:\newline−4×1=(s+1)-4 \times 1 = (s + 1)\newline−4=s+1-4 = s + 1\newlineNow we subtract 11 from both sides to solve for ss.
  4. Solve for ss: Subtracting 11 from both sides gives us:\newline−4−1=s-4 - 1 = s\newline−5=s-5 = s\newlineSo, the value of ss is −5-5.

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