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A line with a slope of 22 passes through the points (−6,6)(-6,6) and (−7,z)(-7,z). What is the value of zz?\newlinez=___z = \_\_\_

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Full solution

Q. A line with a slope of 22 passes through the points (−6,6)(-6,6) and (−7,z)(-7,z). What is the value of zz?\newlinez=___z = \_\_\_
  1. Understand slope formula: Step 11: Understand the slope formula, which is (y2−y1)/(x2−x1)(y_2 - y_1) / (x_2 - x_1). We know the slope is 22, and we have the points (−6,6)(-6, 6) and (−7,z)(-7, z).
  2. Plug values into formula: Step 22: Plug the values into the slope formula. Slope = (z−6)/(−7+6)=(z−6)/−1(z - 6) / (-7 + 6) = (z - 6) / -1. Set this equal to 22 because the slope is given as 22.
  3. Solve for z: Step 33: Solve for z. 2=z−6−12 = \frac{z - 6}{-1}. Multiply both sides by −1-1 to get −2=z−6-2 = z - 6.
  4. Isolate zz: Step 44: Add 66 to both sides to isolate zz. z=4z = 4.

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