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A line with a slope of −2-2 passes through the points (−4,s)(-4,s) and (−9,3)(-9,3). What is the value of ss?\newlines = ____

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Full solution

Q. A line with a slope of −2-2 passes through the points (−4,s)(-4,s) and (−9,3)(-9,3). What is the value of ss?\newlines = ____
  1. Calculate Slope: Points: (−4,s)(-4, s) and (−9,3)(-9, 3)\newlineSlope: −2-2\newlineSelect the equation that represents the slope of the line.\newlineSlope =y2−y1x2−x1= \frac{y_2 - y_1}{x_2 - x_1}\newline−2=3−s−9−(−4)-2 = \frac{3 - s}{-9 - (-4)}
  2. Simplify Equation: −2=3−s−9+4-2 = \frac{3 - s}{-9 + 4}\newlineSimplify the right side of the equation.\newline−2=3−s−5-2 = \frac{3 - s}{-5}
  3. Isolate Variable: −2=3−s−5-2 = \frac{3 - s}{-5}\newlineMultiply both sides by −5-5 to isolate the variable ss.\newline−2×−5=3−s−5×−5-2 \times -5 = \frac{3 - s}{-5} \times -5\newline10=3−s10 = 3 - s
  4. Solve for ss: 10=3−s10 = 3 - s Solve for ss. 10−3=3−s−310 - 3 = 3 - s - 3 7=−s7 = -s s=−7s = -7

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