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A line with a slope of 00 passes through the points (9,−6)(9,-6) and (8,j)(8,j). What is the value of jj?

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Full solution

Q. A line with a slope of 00 passes through the points (9,−6)(9,-6) and (8,j)(8,j). What is the value of jj?
  1. Calculate Slope Equation: Points: (9,−6)(9, -6) and (8,j)(8, j)\newlineSlope: 00\newlineSelect the equation that represents the slope of the line.\newlineSlope =y2−y1x2−x1= \frac{y_2 - y_1}{x_2 - x_1}\newline0=j−(−6)8−90 = \frac{j - (-6)}{8 - 9}
  2. Simplify Equation: 0=j−(−6)8−90 = \frac{j - (-6)}{8 - 9}\newlineSimplify the right side of the equation.\newline0=j+6−10 = \frac{j + 6}{-1}
  3. Multiply by −1-1: 0=j+6−10 = \frac{j + 6}{-1}\newlineMultiply both sides by −1-1.\newline0×−1=j+6−1×−10 \times -1 = \frac{j + 6}{-1} \times -1\newline0=j+60 = j + 6
  4. Solve for j: 0=j+60 = j + 6\newlineSolve for j.\newline0=j+60 = j + 6\newline0−6=j+6−60 - 6 = j + 6 - 6\newline−6=j-6 = j

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