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A line that includes the points (9,p)(9,p) and (6,6)(6,6) has a slope of 11. What is the value of pp?\newlinep = ____

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Q. A line that includes the points (9,p)(9,p) and (6,6)(6,6) has a slope of 11. What is the value of pp?\newlinep = ____
  1. Identify Points and Slope: Identify the given points and the slope.\newlineWe have two points: (9,p)(9, p) and (6,6)(6, 6), and the slope of the line is given as 11.
  2. Use Slope Formula: Use the slope formula to set up an equation.\newlineThe slope formula is (y2−y1)/(x2−x1)(y_2 - y_1) / (x_2 - x_1). Since the slope is 11, we have:\newline1=(p−6)/(9−6)1 = (p - 6) / (9 - 6)
  3. Simplify and Solve: Simplify the denominator and solve for pp.1=p−631 = \frac{p - 6}{3}Multiply both sides by 33 to isolate p−6p - 6.1×3=(p−6)×331 \times 3 = \frac{(p - 6) \times 3}{3}3=p−63 = p - 6
  4. Find Value of p: Add 66 to both sides to find the value of pp. \newline3+6=p−6+63 + 6 = p - 6 + 6\newline9=p9 = p

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