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A line that includes the points (−8,−4)(-8,-4) and (−2,h)(-2,h) has a slope of −1-1. What is the value of hh?\newlineh=___h = \_\_\_

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Q. A line that includes the points (−8,−4)(-8,-4) and (−2,h)(-2,h) has a slope of −1-1. What is the value of hh?\newlineh=___h = \_\_\_
  1. Identify Points and Slope: Identify the points and the slope given in the problem. Points: (−8,−4)(-8, -4) and (−2,h)(-2, h). Slope =−1= -1.
  2. Use Slope Formula: Use the slope formula: Slope=y2−y1x2−x1\text{Slope} = \frac{y_2 - y_1}{x_2 - x_1}. Substitute the given values: −1=h−(−4)−2−(−8)-1 = \frac{h - (-4)}{-2 - (-8)}.
  3. Simplify Equation: Simplify the equation: −1=h+46.-1 = \frac{h + 4}{6}.
  4. Solve for h: Solve for hh: −1×6=h+4-1 \times 6 = h + 4.
  5. Continue Solving: Continue solving: −6=h+4-6 = h + 4.
  6. Isolate hh: Isolate hh: −6−4=h-6 - 4 = h. h=−10h = -10.

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