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A line that includes the points (7,p)(-7,p) and (8,5)(-8,5) has a slope of 5-5. What is the value of pp?\newlinep = ____

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Q. A line that includes the points (7,p)(-7,p) and (8,5)(-8,5) has a slope of 5-5. What is the value of pp?\newlinep = ____
  1. Slope Formula: The slope of a line passing through two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the formula:\newlineslope = y2y1x2x1\frac{y_2 - y_1}{x_2 - x_1}\newlineWe are given the slope of the line as 5-5, and the coordinates of the two points as (7,p)(-7, p) and (8,5)(-8, 5). We can plug these values into the slope formula to find pp.
  2. Substitute Values: Using the slope formula:\newline5=5p8(7)-5 = \frac{5 - p}{-8 - (-7)}\newline5=5p8+7-5 = \frac{5 - p}{-8 + 7}\newline5=5p1-5 = \frac{5 - p}{-1}\newlineNow we need to solve for pp.
  3. Solve for p: To solve for p, we multiply both sides of the equation by 1-1 to get rid of the denominator:\newline5×(1)=(5p)×(1)/(1)-5 \times (-1) = (5 - p) \times (-1) / (-1)\newline5=p55 = p - 5\newlineNow we need to isolate pp by adding 55 to both sides of the equation.
  4. Isolate pp: Adding 55 to both sides of the equation gives us:\newline5+5=p5 + 5 = p\newline10=p10 = p\newlineSo, the value of pp is 1010.

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