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A line that includes the points (−6,−1)(-6,-1) and (−5,h)(-5,h) has a slope of −7-7. What is the value of hh?\newlineh=___h = \_\_\_

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Q. A line that includes the points (−6,−1)(-6,-1) and (−5,h)(-5,h) has a slope of −7-7. What is the value of hh?\newlineh=___h = \_\_\_
  1. Identify Points and Slope: Identify the points and slope given in the problem. Points: (−6,−1)(-6, -1) and (−5,h)(-5, h). Slope: −7-7. Use the slope formula: Slope=y2−y1x2−x1\text{Slope} = \frac{y_2 - y_1}{x_2 - x_1}.
  2. Use Slope Formula: Plug in the values into the slope formula. −7=h−(−1)−5−(−6)-7 = \frac{h - (-1)}{-5 - (-6)}. Simplify the equation. −7=h+1−5+6-7 = \frac{h + 1}{-5 + 6}.
  3. Simplify Equation: Simplify further. −7=(h+1)−1-7 = \frac{(h + 1)}{-1}. Multiply both sides by −1-1 to isolate h+1h + 1. 7=h+17 = h + 1.
  4. Solve for h: Solve for h. Subtract 11 from both sides. 7−1=h7 - 1 = h. h=6h = 6.

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