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A line that includes the points (−5,p)(-5,p) and (−6,−4)(-6,-4) has a slope of −5-5. What is the value of pp?\newlinep=___p = \_\_\_

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Full solution

Q. A line that includes the points (−5,p)(-5,p) and (−6,−4)(-6,-4) has a slope of −5-5. What is the value of pp?\newlinep=___p = \_\_\_
  1. Use slope formula: Use the slope formula to set up the equation. Slope = (y2−y1)/(x2−x1)(y_2 - y_1) / (x_2 - x_1). Here, slope = −5-5, y2=py_2 = p, y1=−4y_1 = -4, x2=−5x_2 = -5, and x1=−6x_1 = -6.
  2. Simplify equation: Simplify the equation.
  3. Solve for pp: Solve for pp by isolating it on one side of the equation.

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