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A line that includes the points (5,−7)(5,-7) and (8,j)(8,j) has a slope of 44. What is the value of jj?\newlinej=j = ____

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Q. A line that includes the points (5,−7)(5,-7) and (8,j)(8,j) has a slope of 44. What is the value of jj?\newlinej=j = ____
  1. Identify Points and Slope: Identify the points and slope.\newlinePoints: (5,−7)(5, -7) and (8,j)(8, j)\newlineSlope: 44\newlineUse the slope formula: Slope =y2−y1x2−x1= \frac{y_2 - y_1}{x_2 - x_1}\newline4=j−(−7)8−54 = \frac{j - (-7)}{8 - 5}
  2. Use Slope Formula: Simplify the equation.\newline4=j+734 = \frac{j + 7}{3}\newlineMultiply both sides by 33 to isolate jj.\newline4×3=(j+7)4 \times 3 = (j + 7)\newline12=j+712 = j + 7
  3. Simplify Equation: Solve for jj.\newlineSubtract 77 from both sides.\newline12−7=j12 - 7 = j\newline5=j5 = j

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