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A line that includes the points (−4,p)(-4,p) and (−3,−6)(-3,-6) has a slope of −7-7. What is the value of pp?\newlinep = ____

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Q. A line that includes the points (−4,p)(-4,p) and (−3,−6)(-3,-6) has a slope of −7-7. What is the value of pp?\newlinep = ____
  1. Points and Slope: Points: (−4,p)(-4, p) and (−3,−6)(-3, -6)\newlineSlope: −7-7\newlineSelect the equation that represents the slope of the line.\newlineSlope =y2−y1x2−x1= \frac{y_2 - y_1}{x_2 - x_1}\newline−7=−6−p−3−(−4)-7 = \frac{-6 - p}{-3 - (-4)}
  2. Calculate Slope: −7=−6−p−3+4-7 = \frac{-6 - p}{-3 + 4}\newlineSimplify the right side of the equation.\newline−7=−6−p1-7 = \frac{-6 - p}{1}
  3. Simplify Equation: −7=−6−p-7 = -6 - p\newlineSolve for pp.\newline−7+6=−6−p+6-7 + 6 = -6 - p + 6\newline−1=−p-1 = -p\newlinep=1p = 1

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