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A line that includes the points (4,j)(4,j) and (5,0)(5,0) has a slope of −7-7. What is the value of jj?\newlinej=___j = \_\_\_

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Q. A line that includes the points (4,j)(4,j) and (5,0)(5,0) has a slope of −7-7. What is the value of jj?\newlinej=___j = \_\_\_
  1. Identify Points and Slope: Identify the given points and the slope.\newlineWe have the points (4,j)(4, j) and (5,0)(5, 0) and the slope of the line is −7-7.\newlineWe will use the slope formula which is slope =(y2−y1)(x2−x1)= \frac{(y_2 - y_1)}{(x_2 - x_1)}.
  2. Plug Values into Formula: Plug the values into the slope formula.\newline−7=0−j5−4-7 = \frac{0 - j}{5 - 4}\newlineSimplify the denominator.\newline−7=0−j1-7 = \frac{0 - j}{1}\newline−7=−j-7 = -j
  3. Simplify and Solve: Solve for jj.\newlineMultiply both sides by −1-1 to get the value of jj.\newlinej=7j = 7

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