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A line that includes the points (−10,−2)(-10,-2) and (−9,p)(-9,p) has a slope of −7-7. What is the value of pp?\newlinep=p = ____

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Full solution

Q. A line that includes the points (−10,−2)(-10,-2) and (−9,p)(-9,p) has a slope of −7-7. What is the value of pp?\newlinep=p = ____
  1. Identify Points and Slope: Identify the points and slope given in the problem. Points: (−10,−2)(-10, -2) and (−9,p)(-9, p). Slope: −7-7. Use the slope formula: Slope=y2−y1x2−x1\text{Slope} = \frac{y_2 - y_1}{x_2 - x_1}.
  2. Substitute Values: Substitute the known values into the slope formula. −7=p−(−2)−9−(−10)-7 = \frac{p - (-2)}{-9 - (-10)}.
  3. Simplify Equation: Simplify the equation. −7=p+2−9+10-7 = \frac{p + 2}{-9 + 10}.
  4. Further Simplification: Simplify further. −7=p+21-7 = \frac{p + 2}{1}.
  5. Solve for p: Solve for pp. −7×1=p+2-7 \times 1 = p + 2.
  6. Isolate p: Isolate pp. −7−2=p-7 - 2 = p.
  7. Calculate Final Value: Calculate the final value of pp. p=−9p = -9.

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