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Let’s check out your problem:
A line has a
slope
of
9
9
9
and includes the points
(
8
,
−
8
)
(8,-8)
(
8
,
−
8
)
and
(
9
,
g
)
(9,g)
(
9
,
g
)
. What is the value of
g
g
g
?
\newline
g
=
_
_
_
g = \_\_\_
g
=
___
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Math Problems
Algebra 1
Find a missing coordinate using slope
Full solution
Q.
A line has a slope of
9
9
9
and includes the points
(
8
,
−
8
)
(8,-8)
(
8
,
−
8
)
and
(
9
,
g
)
(9,g)
(
9
,
g
)
. What is the value of
g
g
g
?
\newline
g
=
_
_
_
g = \_\_\_
g
=
___
Points and Slope Relation:
Points:
(
8
,
−
8
)
(8, -8)
(
8
,
−
8
)
and
(
9
,
g
)
(9, g)
(
9
,
g
)
\newline
Slope:
9
9
9
\newline
Use the slope formula to relate the points and the slope.
\newline
Slope
=
y
2
−
y
1
x
2
−
x
1
= \frac{y_2 - y_1}{x_2 - x_1}
=
x
2
−
x
1
y
2
−
y
1
\newline
9
=
g
−
(
−
8
)
9
−
8
9 = \frac{g - (-8)}{9 - 8}
9
=
9
−
8
g
−
(
−
8
)
Slope Calculation:
9
=
g
+
8
9
−
8
9 = \frac{g + 8}{9 - 8}
9
=
9
−
8
g
+
8
\newline
Simplify the denominator.
\newline
9
=
g
+
8
1
9 = \frac{g + 8}{1}
9
=
1
g
+
8
Denominator Simplification:
9
=
g
+
8
9 = g + 8
9
=
g
+
8
\newline
Solve for
g
g
g
by subtracting
8
8
8
from both sides.
\newline
9
−
8
=
g
+
8
−
8
9 - 8 = g + 8 - 8
9
−
8
=
g
+
8
−
8
\newline
1
=
g
1 = g
1
=
g
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4
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,
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2
)
and
(
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,
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)
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)
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3
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8
)
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(
3
,
8
)
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1
1
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−
1
4
-\frac{1}{4}
−
4
1
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4
4
4
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−
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4
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1
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1
,
−
7
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1
,
−
7
)
and
(
3
,
9
)
(3,9)
(
3
,
9
)
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\newline
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1
1
1
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1
4
\frac{1}{4}
4
1
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4
4
4
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4
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1
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