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A line has a slope of −7-7 and includes the points (8,10)(8,10) and (10,z)(10,z). What is the value of zz?\newlinez=___z = \_\_\_

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Q. A line has a slope of −7-7 and includes the points (8,10)(8,10) and (10,z)(10,z). What is the value of zz?\newlinez=___z = \_\_\_
  1. Identify slope formula: Step 11: Identify the formula for the slope between two points.\newlineThe slope formula is (y2−y1)/(x2−x1)(y_2 - y_1) / (x_2 - x_1). Here, (x1,y1)=(8,10)(x_1, y_1) = (8, 10) and (x2,y2)=(10,z)(x_2, y_2) = (10, z).
  2. Substitute known values: Step 22: Substitute the known values into the slope formula.\newlineSlope = −7-7, so:\newline−7=z−1010−8-7 = \frac{z - 10}{10 - 8}
  3. Solve for zz: Step 33: Solve for zz.\newline−7=z−102-7 = \frac{z - 10}{2}\newlineMultiply both sides by 22 to clear the fraction:\newline−14=z−10-14 = z - 10\newlineAdd 1010 to both sides:\newline−4=z-4 = z

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