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A line has a slope of −4-4 and includes the points (4,−6)(4,-6) and (2,h)(2,h). What is the value of hh?\newlineh = ____

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Q. A line has a slope of −4-4 and includes the points (4,−6)(4,-6) and (2,h)(2,h). What is the value of hh?\newlineh = ____
  1. Calculate Slope: Points: (4,−6)(4, -6) and (2,h)(2, h)\newlineSlope: −4-4\newlineUse the slope formula to find the relationship between the points.\newlineSlope =y2−y1x2−x1= \frac{y_2 - y_1}{x_2 - x_1}\newline−4=h−(−6)2−4-4 = \frac{h - (-6)}{2 - 4}
  2. Simplify Equation: Simplify the right side of the equation.\newline−4=(h+6)(2−4)-4 = \frac{(h + 6)}{(2 - 4)}\newline−4=(h+6)−2-4 = \frac{(h + 6)}{-2}
  3. Isolate Variable: Multiply both sides by −2-2 to isolate hh.−4×(−2)=h+6−2×(−2)-4 \times (-2) = \frac{h + 6}{-2} \times (-2)8=h+68 = h + 6
  4. Solve for h: Solve for h.\newline8=h+68 = h + 6\newline8−6=h+6−68 - 6 = h + 6 - 6\newline2=h2 = h

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