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A line has a slope of 1010 and includes the points (−1,9)(-1,9) and (−2,c)(-2,c). What is the value of cc?\newlinec=c = ____

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Full solution

Q. A line has a slope of 1010 and includes the points (−1,9)(-1,9) and (−2,c)(-2,c). What is the value of cc?\newlinec=c = ____
  1. Identify Points and Slope: Identify the points and slope given in the problem. Points: (−1,9)(-1, 9) and (−2,c)(-2, c). Slope: 1010. Use the slope formula: Slope=(y2−y1)(x2−x1)\text{Slope} = \frac{(y_2 - y_1)}{(x_2 - x_1)}.
  2. Use Slope Formula: Simplify the denominator and solve for cc. 10=c−9−110 = \frac{c - 9}{-1}.
  3. Simplify and Solve for cc: Isolate cc by adding 99 to both sides. −10+9=c−9+9-10 + 9 = c - 9 + 9.

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