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A line has a slope of −1-1 and includes the points (−3,d)(-3,d) and (−8,4)(-8,4). What is the value of dd?\newlined = ____

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Q. A line has a slope of −1-1 and includes the points (−3,d)(-3,d) and (−8,4)(-8,4). What is the value of dd?\newlined = ____
  1. Identify Given Points and Slope: Identify the given points and the slope.\newlineWe have the points (−3,d)(-3, d) and (−8,4)(-8, 4) with a slope of −1-1.\newlineThe formula for the slope mm between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}.
  2. Plug Values into Slope Formula: Plug the given values into the slope formula.\newlineUsing the slope formula with our given slope and points, we get:\newline−1=4−d−8−(−3)-1 = \frac{4 - d}{-8 - (-3)}
  3. Simplify Denominator: Simplify the denominator of the fraction.\newline−1=4−d−8+3-1 = \frac{4 - d}{-8 + 3}\newline−1=4−d−5-1 = \frac{4 - d}{-5}
  4. Multiply by −5-5: Multiply both sides by −5-5 to solve for dd.−1×(−5)=(4−d)×(−5)/(−5)-1 \times (-5) = (4 - d) \times (-5) / (-5)5=4−d5 = 4 - d
  5. Solve for dd: Solve for dd by isolating it on one side of the equation.\newline5=4−d5 = 4 - d\newline5−4=−d5 - 4 = -d\newline1=−d1 = -d\newlined=−1d = -1

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