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A function f(x)f(x) is defined by f(x)=2x2+7f(x)=2x^2+7. What is the value of 2f(x)−32f(x)-3?

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Full solution

Q. A function f(x)f(x) is defined by f(x)=2x2+7f(x)=2x^2+7. What is the value of 2f(x)−32f(x)-3?
  1. Calculate 2f(x)2f(x): We know f(x)=2x2+7f(x) = 2x^2 + 7.\newlineCalculate 2f(x)2f(x): \newline2f(x)=2(2x2+7)=4x2+142f(x) = 2(2x^2 + 7) = 4x^2 + 14.
  2. Subtract 33 from 22f(x): Now, subtract 33 from 22f(x):\newline2f(x)−3=(4x2+14)−3=4x2+112f(x) - 3 = (4x^2 + 14) - 3 = 4x^2 + 11.

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