A bowl contains 12 green candies, 4 yellow candies, and some red candies. The probability of choosing a green candy at random is twice as great as the probability of choosing a red candy at random. What is the probability of choosing a yellow candy at random?E. (2)/(11)F. (2)/(9)G. (1)/(4)H. (3)/(11)
Q. A bowl contains 12 green candies, 4 yellow candies, and some red candies. The probability of choosing a green candy at random is twice as great as the probability of choosing a red candy at random. What is the probability of choosing a yellow candy at random?E. (2)/(11)F. (2)/(9)G. (1)/(4)H. (3)/(11)
Identify Red Candies: Let's find out how many red candies there are. We know the probability of picking a green candy is twice that of picking a red candy. Let's denote the number of red candies as r. The total number of candies is 12 (green) + 4 (yellow) + r (red) = 16+r.
Calculate Probability Equation: The probability of picking a green candy is 16+r12, and the probability of picking a red candy is 16+rr. Since the probability of picking a green candy is twice that of a red candy, we have:16+r12=2×(16+rr).
Solve for Number of Red Candies: Solving the equation: 16+r12=16+r2r,12=2r,r=6.
Calculate Total Number of Candies: Now, we know there are 6 red candies. The total number of candies is 12+4+6=22.
Calculate Probability of Yellow Candy: The probability of picking a yellow candy is the number of yellow candies divided by the total number of candies, which is 224. Simplifying this gives:224=112.
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