A bag contains 7 red marbles, 5 blue marbles and 3 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 1oth of a percent, that both marbles drawn will be red? Answer:

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Calculate Total Marbles: First, we need to determine the total number of marbles in the bag. Total marbles = red marbles + blue marbles + green marbles Total marbles = 7 + 5 + 3 Total marbles = 15Calculate Probability of First Red Marble: Next, we calculate the probability of drawing one red marble on the first draw. Probability of first red marble = Number of red marbles / Total number of marbles Probability of first red marble = 7 / 15Update Marbles After First Draw: After drawing one red marble, there is one less red marble and one less total marble in the bag. New number of red marbles = Original number of red marbles - 1 New number of red marbles = 7 - 1 New number of red marbles = 6 New total number of marbles = Original total number of marbles - 1 New total number of marbles = 15 - 1 New total number of marbles = 14Calculate Probability of Second Red Marble: Now, we calculate the probability of drawing a second red marble after the first one has been drawn. Probability of second red marble = New number of red marbles / New total number of marbles Probability of second red marble = 6 / 14Multiply Probabilities for Both Red Marbles: To find the probability of both events happening (drawing two red marbles in a row), we multiply the probabilities of each individual event. Probability of both red marbles = Probability of first red marble × Probability of second red marble Probability of both red marbles = (7 / 15) × (6 / 14) Probability of both red marbles = (7 × 6) / (15 × 14) Probability of both red marbles = 42 / 210Simplify Probability Fraction: Simplify the fraction to find the probability in its simplest form. Probability of both red marbles = 42 / 210 Probability of both red marbles = 1 / 5Convert Probability to Percentage: Finally, we convert the probability to a percentage to the nearest tenth of a percent. Probability as a percent = Probability of both red marbles × 100% Probability as a percent = (1 / 5) × 100% Probability as a percent = 20%

A bag contains $7$ red marbles, $5$ blue marbles and $3$ green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest $1$ oth of a percent, that both marbles drawn will be red? $\newline$ Answer:

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A bag contains $7$ red marbles, $5$ blue marbles and $3$ green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest $1$ oth of a percent, that both marbles drawn will be red? $\newline$ Answer: